Introduction to right hexagonal prism
A right prism is a prism within which the apex and base polygons lie down on the top of every other.Therefore to the vertical polygons joining their faces are not only parallelograms, but rectangles. A prism to be not a right prism is recognized as an oblique prism. If, also, the higher and inferior bases are rectangles, after that the prism is recognized as a cuboid.
Right Hexagonal Prism
A hexagonal prism is a prism collected of 6 rectangular faces and 2 hexagonal bases. It is also identified as octahedron.
The usual right hexagonal prism of edge length a contain surface area also volume.
`S=3(2+sqrt(3))a^2`
`V=3/2sqrt(3)a^3`
The usual right hexagonal prism is a gap-filling polyhedron.
Examples for Right Hexagonal Prism
Example 1
Find the volume of a right hexagonal prism to contain base edges of 11 meters and a height of 30 meters?
Solution:
Given
height = 30 m
base edge = 11 m
The six sides of the bottom hexagon are all of length 11m.
Let us consider the mean to the hexagon is regular.
Area of a regular hexagon of side a is `A=(3 sqrt(3))/2 a^2`
Therefore the base area of the prism is `A=(3 sqrt(3))/2xx 11^2`
A = 112 x 2.6 {since `(3 sqrt(3))/2` =2.6}
= 121 x 2.6
Area of the hexagon = 314.6 m2
Volume of a right prism is V = Ah
Wherever A - base area
h - Height.
Therefore the volume of prism is V = 314.6 x 30
Therefore the volume of prism is V=9438 m2
Example 2
Find the volume of a right hexagonal prism to contain base edges of 16 meters and a height of 40 meters?
Solution:
Given
height = 40 m
base edge = 16 m
The six sides of the bottom hexagon are all of length 16 m.
Let us consider the mean to the hexagon is regular.
Area of a regular hexagon of side a is `A=(3 sqrt(3))/2 a^2`
Therefore the base area of the prism is `A=(3 sqrt(3))/2xx 16^2`
A = 162 x 2.6 {since `(3 sqrt(3))/2` =2.6}
= 256 x 2.6
Area of the hexagon = 665.6 m2
Volume of a right prism is V = Ah
Wherever A - base area
h - Height.
Therefore the volume of prism is V = 665.6 x 40
Therefore the volume of prism is V=26624 m2
A right prism is a prism within which the apex and base polygons lie down on the top of every other.Therefore to the vertical polygons joining their faces are not only parallelograms, but rectangles. A prism to be not a right prism is recognized as an oblique prism. If, also, the higher and inferior bases are rectangles, after that the prism is recognized as a cuboid.
Right Hexagonal Prism
A hexagonal prism is a prism collected of 6 rectangular faces and 2 hexagonal bases. It is also identified as octahedron.
The usual right hexagonal prism of edge length a contain surface area also volume.
`S=3(2+sqrt(3))a^2`
`V=3/2sqrt(3)a^3`
The usual right hexagonal prism is a gap-filling polyhedron.
Examples for Right Hexagonal Prism
Example 1
Find the volume of a right hexagonal prism to contain base edges of 11 meters and a height of 30 meters?
Solution:
Given
height = 30 m
base edge = 11 m
The six sides of the bottom hexagon are all of length 11m.
Let us consider the mean to the hexagon is regular.
Area of a regular hexagon of side a is `A=(3 sqrt(3))/2 a^2`
Therefore the base area of the prism is `A=(3 sqrt(3))/2xx 11^2`
A = 112 x 2.6 {since `(3 sqrt(3))/2` =2.6}
= 121 x 2.6
Area of the hexagon = 314.6 m2
Volume of a right prism is V = Ah
Wherever A - base area
h - Height.
Therefore the volume of prism is V = 314.6 x 30
Therefore the volume of prism is V=9438 m2
Example 2
Find the volume of a right hexagonal prism to contain base edges of 16 meters and a height of 40 meters?
Solution:
Given
height = 40 m
base edge = 16 m
The six sides of the bottom hexagon are all of length 16 m.
Let us consider the mean to the hexagon is regular.
Area of a regular hexagon of side a is `A=(3 sqrt(3))/2 a^2`
Therefore the base area of the prism is `A=(3 sqrt(3))/2xx 16^2`
A = 162 x 2.6 {since `(3 sqrt(3))/2` =2.6}
= 256 x 2.6
Area of the hexagon = 665.6 m2
Volume of a right prism is V = Ah
Wherever A - base area
h - Height.
Therefore the volume of prism is V = 665.6 x 40
Therefore the volume of prism is V=26624 m2
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